Michaelis-Menten Expression (MME):

V0= Vmax*[S] / (Km + [S])

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We know regardless of [S], Km= 1x10^-4 for this enzyme.

Observation A ([S] = 0.2M), MME:

4.3x10^4 = 0.2*Vmax_a / (1x10^-4 + 0.2)

Observation B ([S] = 0.02M), MME:

4.3x10^4 = 0.02*Vmax_b / (1x10^-4 + 0.02)

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Therefore:

0.2*Vmax_a / (1x10^-4 + 0.2) = 0.02*Vmax_b / (1x10^-4 + 0.02)

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