How many moles of NaHCO3 are in 44g?

Moles = Mass / Mr Mass = 44g Mr = Na (1x23.0) + H (1x1.0) + C (1 x 12.0) + O (3 x 16.0) = 84.0 Moles = 44g / 84.0 = 0.524 moles

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To calculate Moles you do Mass/Mr Mass= 44g Mr= 84 g/mol Moles= 44/84 Moles= 0.52 mol

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Chemistry Tutor • Undergraduate

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