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20 cu. cm. of calcium chloride (CaCl2) contains the most number of chloride ions. Here is the explanation: 1. AlCl3: Concentration: 3.3 x 10^-2 mol/dm3 (Given) Volume: 10 cm3 = 10^-2 dm3 (Given) Total moles of AlCl3: = Concentration (which is no. of moles per unit volume) x Volume = (3.3 x 10^-2 mol/dm3) x (10^-2 dm3) = 3.3 x 10^-4 mol 1 mole of AlCl3 ionizes to produce 3 moles of chloride ions (since AlCl3 molecule contains 3 atoms of Cl). Therefore, no. of Cl ions in 3.3 x 10^-4 mol of AlCl3: = 3 x 3.3 x 10^-4 mol = 9.9 x 10^-4 mol Try to similarly calculate the number of Cl ions for the remaining compounds. You can check your calculations here: Total mol. of Cl in: 20cm3 of 5 x 10^-2 mol/dm3 CaCl2 = 2x10^-3 (or 0.002) 30cm3 of 3.3 x 10^-2 mol/dm3 HCl = 9.9x10^-4 (or 0.00099) 40cm3 of 2.5 x 10^-2 mol/dm3 NaCl = 10^-3 (or 0.001) As you can check, 20cm3 of 5 x 10^-2 mol/dm3 CaCl2 contains the highest number of Cl ions
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