A weather balloon has a volume 1750L at 1.016 atm and is released into the atmosphere. At the highest point above the ground, the pressure is 35.0 kPa. What’s the volume of the balloon?
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1.016 atm converted to kPa = 102.946 kPa Use Boyle’s Law P1 V1 = P2 V2 So 1750 x 102.946 =35 V2 From this V2 = (1750x 102.946)/35 So V2 = 5247.3 Lt
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