10 students who play football and cricket 7 students who do not play football or cricket 14 students who play football 21 students who play cricket Find the probability that student chosen at random plays football and cricket?
Probability is #of students who play both/#of students total. I assume from the wording that the "students playing football" includes those who also play cricket and vice versa. Therefore there are 14-10=4 students who play only football and 21-10=11 students who play just cricket. Probability is 10/(10+7+4+11)=10/32=5/16
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