A right angled triangle with one side 5.7 cm and the other 6.3 cm what is x (the short side, base)?
Longest side is the hypotenuse so by Pythagoras (6.3)^2 = (5.7)^2 + x^2 Rearranging x = Sqrt((6.3)^2 - (5.7)^2) So x = 2.68 3sf
For this question you need to use Pythagoras' Theorem: the square of the hypotenuse (the longest side, which is opposite the right angle) is equal to the sum of the squares of the other two sides. This is commonly written as: a^2 = b^2 + c^2. In this question the longest side is 6.3, so that is a. And 5.7 is one of the other sides. So you can find the missing side by calculating: a^2 - b^2 = c^2 6.3^2 - 5.7^2 = x^2 squareroot(6.3^2 - 5.7^2) = x = 2.68 (3.s.f.)
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