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A right angled triangle with one side 5.7 cm and the other 6.3 cm what is x (the short side, base)?

2 answers
Answered Feb 19Maths
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Dr. Badi MExperienced Academic and dedicated tutor for all levels.

Longest side is the hypotenuse so by Pythagoras (6.3)^2 = (5.7)^2 + x^2 Rearranging x = Sqrt((6.3)^2 - (5.7)^2) So x = 2.68 3sf

Answered May 18Maths
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Mekha Sanjeev..............124 students helped

For this question you need to use Pythagoras' Theorem: the square of the hypotenuse (the longest side, which is opposite the right angle) is equal to the sum of the squares of the other two sides. This is commonly written as: a^2 = b^2 + c^2. In this question the longest side is 6.3, so that is a. And 5.7 is one of the other sides. So you can find the missing side by calculating: a^2 - b^2 = c^2 6.3^2 - 5.7^2 = x^2 squareroot(6.3^2 - 5.7^2) = x = 2.68 (3.s.f.)