Let Volume of pool be V and flow rate of first hose be R1

For first hose we then get V=(R1)(x)

Let flow rate of second hose be R2

For second hose we get equation

V=(R2)(y) (same volume V to be filled)

Using both hoses, the flow rate then become (R1+R2), with time m days

So equation 3 is V=(R1+R2)m

Substituting equation 1 and 2 into 3 for R1 and R2 we get

V=((V/x)+(V/y))m

Cancel out V (only p... more

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Joseph Guillon
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6 months ago


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