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Express 540 as a product of its prime factor?

2 answers
Dr. Badi MExperienced Academic and dedicated tutor for all levels.17.5k students helped

A prime number is one which does not divide into multiples of smaller numbers and are all odd numbers so not divisible by 2. For 540 you start by divide it by the smallest prime number as many times until no more 2 is available ie (540/2)=270 then (270/2) = 135 then this odd so divide by 3 (135/3) = 45. again odd so divide by 3 (45/3)= 15 repeat this (15/3)=5 so now you stop no more division So 540= 2x2x3x3x3x5 These are the prime cofactors or rewritten 2^2x3^3x5^1 Or 2^2x3^3x5

Dr. Badi MExperienced Academic and dedicated tutor for all levels.17.5k students helped

A prime number is one which does not divide into multiples of smaller numbers and are all odd numbers so not divisible by 2. For 540 you start by divide it by the smallest prime number as many times until no more 2 is available ie (540/2)=270 then (270/2) = 135 then this odd so divide by 3 (135/3) = 45. again odd so divide by 3 (45/3)= 15 repeat this (15/3)=5 so now you stop no more division So 540= 2x2x3x3x3x5 These are the prime cofactors or rewritten 2^2x3^3x5^1 Or 2^2x3^3x5

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