Asked by Lacey

#### Express 540 as a product of its prime factor?

A prime factor tree would be a good method to use here. First think of 2 numbers that multiply to get 540, the most obvious ones are 54 and 10. Now both of these are not prime numbers. So we'll look at 10 first, which is a product of 5 and 2 and both of these are primes so we are finished with 10. Now looking at 54, we can see that 9 and 6 are factors (as well as 2 and 27, 3 and 18). Both 9 and 6... more

Unfortunately, I can’t reply to you with a picture, but if you know what a prime factor tree is, that’s a helpful way to work through each step visually.

This is how you’d do one for the number 16: https://socratic.org/questions/what-is-a-prime-factor-tree-of-16

The fact that 2 goes into 540 would be a good place to start!

Hope that helps!

A prime number is one which does not divide into multiples of smaller numbers and are all odd numbers so not divisible by 2.

For 540 you start by divide it by the smallest prime number as many times until no more 2 is available ie

(540/2)=270 then

(270/2) = 135 then this odd so divide by 3

(135/3) = 45. again odd so divide by 3

(45/3)= 15 repeat this

(15/3)=5 so now you stop no more division

So 5... more

A prime number is one which does not divide into multiples of smaller numbers and are all odd numbers so not divisible by 2.

For 540 you start by divide it by the smallest prime number as many times until no more 2 is available ie

(540/2)=270 then

(270/2) = 135 then this odd so divide by 3

(135/3) = 45. again odd so divide by 3

(45/3)= 15 repeat this

(15/3)=5 so now you stop no more division

So 5... more

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