# Express x^5/(2x-7x^2) in 2x^p-7x^q?

### VERIFIED

### Nicholas Hutter

Actuarial Science student at LSE with over 7 years tutoring experience.

x^5 / x(2 - 7x) take out a common x in the denominator x^4 / (2 - 7x) cancel out an x 1/ x^-4 (2-7x) bring down the x^4 to the denominator 1/ (2x^-4 - 7x^-3) Multiply the x^-4 in (2x^-4 - 7x^-3)^-1

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