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# Find the size of angle xyz z |\ | \ 15 | \ Cm |_ right angle |_|____ \ x 6cm y?

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ hypotenuse => sin(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ hypotenuse => sin(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.  Samuel Osei-Wusu
·

14.9k students helped

Maths

6(1/2)^n-1

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