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Asked by HygeiaGiven4×5∧3+2×5∧2+5p=4230base5, find the value of p?
4230 base 5 = 0*5^0 + 3*5^1 + 2*5^2 + 4*5^3 4230 base 5 = 565 base 10 Therefore, 565 = 4*5^3 + 2*5^2 + 5p 5p = 15 p = 3
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