First, you want to find the lower and upper bounds of the circumference C and diameter D.

C = 405mm to 3sf so the bounds are:

404.5 to 405.5

We find this by subtracting/adding half the degree of accuracy. Here it is 1mm, looking at 3rd significant figure.

D = 130mm to 2sf so the bounds are:

125 to 135

Here the degree of accuracy is 10mm, looking at the 2nd significant figure.

Now you conside... more

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Mekha Sanjeev
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124 students helped

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3 years ago

If we’re looking for the lowerbound of pi, the circumference C would have to be at its smallest and the diameter D would have to be at its highest. For the upper bound it would be the other way around.

So for the lower bound:

405mm (3 s.f.) => 404.5 (lowest possible)

130mm (2 s.f.) => 134.499... (highest possible)

lower bound pi = 3.007 (3d.p)

So for the higher bound:

405mm (3 s.f.) => 405.49... more

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Mujavid Bukhari
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140 students helped

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3 years ago

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