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# How do I find the gradient of the line with the equation 2y+3x=12 & also if the line crosses the yaxis at (0,c) the value of C?

Hi Emma 2y+3x=12 12-2y 3x=12-2y 3x/3=12/3-2y/3 X=12-2y/3

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239 students helped

Hi Emma, I'll put the working out here and the explanation below. y=Mx+c 2y=-3x+12 y=-3/2x + 6 So gradient 'm' = -3/2 (0,c) 2y+3(0)=12 y=12÷2=2 First thing is that the equation must be in the form 'y=mx+c'. So you need to take the 3x to the right which makes the equation 2y=-3x+12. Next you need to take the 2 to the right, dividing all the terms in the right,so the equation becomes y=-3/2x + 6. Now we know that m is the gradient in y=mx+c, so we can now red it off from our rearranged equation. '-3/2'. Now the second part of your question can be done by simply setting 'x' to 0, 2y+3(0)=12. Y=12÷2=6.

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