MATHS

Asked by StephanieVery easily: 1)how many 32s fit into 6, see the answer is 0 remainder 6, then you move the remainder 6 onto the the second digit 5 to make 65 2)how many 32s fit into 65, the answer is 2 remainder 1. You move that 1 to the next digit to make 19 3)how many 32s fit into 19. Answer=0 remainder 19. So the answer is 20 remainder 19 This is called long division which can be used with any division including decimals.

I can’t really answer this without drawing a diagram to show you. But what helped me out a bunch was something called the ‘bus stop method’. It’s very easy to understand and remember for divisions like this. Message me for info if you need but definitely look up the bus stop method.

You can use the DMS method 1) D-ivide 2) M-ultiply 3)S - Subtract 32√659. Step by Step Solution 1) D 21 32√659 (Ask your self how many 32's go in to 659) - use approximation so how many 30s go in to 659 about 21 2) M Therefore 32 × 21 = 642 21 32√659 642 3) S. (659 - 642 = 17) 21 32√659 -642 17 Therefore 21 r 17 <- Answer 32√659 -642 17 ( √ - represents the long division symbol ) If it's not clear please provide feedback.

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