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# How do you solve this maths problem? The length of a rectangle is 9 more then it’s width. If the perimeter of the rectangle is 110cm, find its width. This is part of my solving equations homework and I don’t understand it. Thank you?

Perimeter of a rectangle is 2(l+w) Where l is the length and w is the width If length is 9 more than it's width then l=9×w => 9w So Perimeter => 2(9w + w) = 110 => 2(10w) = 110 => 10w = 110/2 (divide both sides by 2) => 10w = 55 => w = 55/10 (divide both sides by 10) Therefore the width is 5.5cm

Samuel Osei-Wusu
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