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MATHS
Asked by Domenica

How do you solve this maths problem? The length of a rectangle is 9 more then it’s width. If the perimeter of the rectangle is 110cm, find its width. This is part of my solving equations homework and I don’t understand it. Thank you?

Hi Domenica, For the question, we want to form an equation. We want to make the 110 (the perimeter) = something Let's call the width x As the length is 9 times longer than the width, the length is 9x In a rectangle, we have 2 width measurements and 2 length measurements. So 9x + 9x + x +x = 110 Add up all the x all the left hand side, we get 20x So 20x =110 Dividing both sides by 20, means that x = 5.5 ( We don't want to know what 20 x is , we just want to know what x is) We now know that the width is 5.5cm Hope this is clear. If you'd like further clarification, please let me know.

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Emma Berwick
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Perimeter of a rectangle is 2(l+w) Where l is the length and w is the width If length is 9 more than it's width then l=9×w => 9w So Perimeter => 2(9w + w) = 110 => 2(10w) = 110 => 10w = 110/2 (divide both sides by 2) => 10w = 55 => w = 55/10 (divide both sides by 10) Therefore the width is 5.5cm

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Samuel Osei-Wusu
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