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# If a linear sequence had a common difference of 8, what are the three consecutive terms in the sequence which add up to give a total of 126?

Since the three terms are consecutive and have a difference of 8, I can write these terms as k, k+8, k+16 The total of these should be 126: k + k+8 + k+16 = 3k+24 = 126 Solving for k, we get: 3k = 102 k = 34 So, our three terms are: 34, 42, 50 Hope that helps! ~ Sohini  Sohini Khan
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Maths

2x+x+x+2y×3y×y

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