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Asked by Faith

Possible formuna for the nth term of a sequence of 37 33 29 25 21?

If we take 37 as the 0th term, then the nth term can be found as 37-4n, as each following number is smaller by a common difference of 4. For example: 4th term (21) = 37-4*4 = 37-16 = 21. If we consider 37 to be the 1st term, we need to make a small change to our formula: 37-4(n-1) Now: 5th term (21) = 37-4*(5-1) = 37-16 = 21.

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