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Asked by Iris

Sequence of series (n-2)^2?

n is just a term so we can substitute values into it. In this sequence, when n=1 (1-2)^2 => -1^2=1 when n=2 (2-2)^2 => 0^2=0 when n=3 (3-2)^2 => 1^2=1 Therefore the sequence is 1,0,1 ...

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Amelia Kirkham
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In these questions 'n' is the position of terms, so when n=1 it means what is the first term. When n=2 it means what is the 2nd term. Here, the first term n=1 would be (1-2)^2 which is -1^2 = 1, remember square numbers are always positive. n=2 is the 2nd term, (2-2)^2 is 0^2 = 0.

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Ganesh Nair
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When n=1, (1-2)^2 is 1. When n=2, (2-2)^2 is 0. When n=3, (3-2)^2 is 1, When n=4, (4-2)^2 is 4 and so on

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Jonathon Franklin
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