MATHS

Asked by TttThis is hard to illustrate without drawing, but essentially here’s the solution. One of the rectangle lengths will be twice the width of the circle. The width of a circle is 2*2m = 4m, so the side length of the rectangle is 8m. There is an equilateral triangle of side-length 2m formed by the centre of these circles. Each internal angle of such a triangle is 60 degrees. We can use trigonometry to show that the remaining side of the triangle is 2*2m + tan(60)*2m = (4+√3)m The area is the product of these two lengths: 8m*(4+√3)m = (8√3+32)m^2 See the following image for a visual depiction: https://i2.wp.com/mindyourdecisions.com/blog/wp-content/uploads/2019/05/rectangle-area-from-3-circles-hard-gcse-maths-problem-solution.png?w=600&ssl=1

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