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# Write the eqaution of the line in the form y=mx+c, q1) which passes through (-5,-2) and (1,0)?

How do we do this? First, find the difference between the two x & y co-ordinates: y² - y¹ = (1 - -5) = 6 x² - x¹ = (0 - -2) = 2 So we now know that for every 6 times y increases, x increases by 2. We can simplify to y being 3 times x. So: Y=3x + c. Now solve for c: Plug in any of the given co-ordinates for x & y: (-5) = 3(-2) + c. OR: (1) = 3(0) + c :. -5 = -6 + c. OR: 1 = c Therefore Y = 3x + 1  ·

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