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PHYSICS
Asked by Faizah

Two stone are thrown from the same point at the same time, 1 vertically upwards with a speed of 20m/s and one vertically downwards at 20m/s find how far apart the stones are after 2 seconds?

Use s=ut+(1/2)at^2 Stone1 S1=20(2)-(1/2)9.81(4) S1=20.38m Stone2 S2=20(2)+(1/2)9.81(4) S2=59.62m Adding s1+s2= 80m

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