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Asked by Ambika

A metal forms 2 oxides the higher oxide contains 80% of meta . 0.72g of the lower oxide gave 0.8 of the higher oxides when oxidized show that the data illustrates the law of multiple proportion?

Let me explain you using an example as follows: Consider the elements carbon and oxygen. Combined in one way, they form the familiar compound called carbon dioxide. In every sample of carbon dioxide, there is 32.0g 32.0g of oxygen present for every 12.0g of carbon. By dividing 32.0 by 12.0, this simplifies to a mass ratio of oxygen to carbon of 2.66 to 1. There is another compound that forms from the combination of carbon and oxygen called carbon monoxide. Every sample of carbon monoxide contains 16.0g of oxygen for every 12.0g of carbon. This is a mass ratio of oxygen to carbon of 1.33 to 1. In the carbon dioxide, there is exactly twice as much oxygen present as there is in the carbon monoxide. This example illustrates the law of multiple proportions: whenever the same two elements form more than one compound, the different masses of one element that combine with the same mass of the other element are in the ratio of small whole numbers. Hope that helps for your problem solutions. Cheers.

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Karan Mahendra Jain
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