GCSE Physics Summary
Revision Notes for GCSE Physics (No Electricity or Waves)
GCSE Maths and Sciences tutor with 5+ Level 9 GCSEs and doing Maths, FM, Physics and DT A-Levels
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Asked by Yusraa
A ball is thrown vertically into the air with an initial velocity of 19m/s. What height will it travel upwards before it starts to reverse its direction?
Initial velocity u = 19m/s Final velocity v = 0m/s at the top Acceleration a = G = - 9.8m/s2 We need the distance s. Equation that contains these variables but not time is V2 = u2 + 2as U2 = - 2as U2 / 2a = - s Putting values in 19^2 / 2 * - 9.8 = - s 361/19.6 = s S=18.41m Ignore the syntax capital lower case etc. Hope this helps
Asked by Holly
A ball is thrown vertically into the air with an initial velocity of 19 m/s. What height will it travel upwards before it starts to reverse its direction?
Given parameters are: Initial velocity of the ball (u) =19m/s. The velocity of the ball at maximum height (v) = 0. g = 9.8m/s^2 Let us consider the maximum height as H. Consider the formula, 2gH = v^2– u^2 2 × (- 9.8) × H = 0 – (19)^2 – 19.6 H = – 361 H = 18.418 m. Therefore, The ball will travel a maximum height of 18.418m upwards before it starts to reverse its direction. Feel free to ping me for any further clarifications. Thanks.
Asked by Holly
A ball is thrown vertically into the air with an initial velocity of 19 m/s. What height will it travel upwards before it starts to reverse its direction?
Given parameters are: Initial velocity of the ball (u) =19m/s. The velocity of the ball at maximum height (v) = 0. g = 9.8m/s^2 Let us consider the maximum height as H. Consider the formula, 2gH = v^2– u^2 2 × (- 9.8) × H = 0 – (19)^2 – 19.6 H = – 361 H = 18.418 m. Therefore, The ball will travel a maximum height of 18.418m upwards before it starts to reverse its direction. Feel free to ping me for any further clarifications. Thanks.
Asked by 『 Мσση
If the voltmeter reads 3V what will the voltage be across each bulb?
Hi Moon, if it’s 3V at the battery with ONE bulb it’s 3V - the same! If it’s TWO bulbs it’s half 1.5V. If it’s THREE bulbs it’s a third -1V. FOUR bulbs divide by 4, so 1V. (In a parallel circuit it would be 3V for every Bulb on each branch, if there’s more than one bulb on each branch it shared like above) Hope that helps!
Asked by Hailey
A petrol engine takes 1000J of chemical energy and does 250J ofwork. What is the efficiency?
Hi Hailey, The efficiency is calculated by dividing the work done by the energy put in and then multiplying by 100% to make it into a percentage. It is essentially working out how much of the energy that is put in is actually used for work (useful energy). So, here the answer would be (250J/1000J) x 100% = 25%. Hope this helps!