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The best way to answer questions like these is with a Venn diagram. You will need to draw 2 circles that slightly overlap. The overlap is both football and cricket so we write 8 in this gap. The question tells us that 14 students play football but doesnt tell us that they only play football. This means that we must subtract 8 from 14 giving us 6. this goes in one circle. The same applies to 20 students that plays cricket so again we minus 8 from 20 giving us 12. This is written in the other circle. We are also told that 4 students do not play either so this is written outside the circles. 

Now we have our Venn diagram we can work out the probability. 
We need to find the total of students so we add all the numbers in the diagram together; 6+8+12+4 = 30

We also need to find the total amount that play cricket or football or both so 6+8+12 = 26 

Therefore the answer is 26/30.

Maths

If there are 8 students who play football and cricket 4 students who do not play football or cricket 14 students who play football and 20 students who play cricket find the probability that a student chosen at random plays football or cricket or both

n is just a term so we can substitute values into it. 

In this sequence, when n=1 
(1-2)^2 => -1^2=1 
when n=2
(2-2)^2 => 0^2=0
when n=3 
(3-2)^2 => 1^2=1

Therefore the sequence is 1,0,1 ...

Sequence of series (n-2)^2

4y when y=-3

In other words the question is asking us to find the answer to 4(y) by substituting in y=-3.

Therefore we substitute y=-3 into 4(y) giving us 4(-3).

We know that if there are brackets we multiple so 4 x -3 which gives us -12 as a positive number multiplied by a negative number always gives a negative answer. 

=-12

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