As one of my lecturers is always reminding us “maths is not a spectator sport”. The best way to learn maths is to do it. Start of by working through an example, then ask yourself how everything in the question fits together. Next, practice  other examples, increase difficulty etc.

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How can i study best for math

Use Gauss’ formula: sum = 1000/2 *(1000+2) = 250500

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Hello, how would I work out the sum of the even numbers between 1 and 1000? Is there an equation I can use? Thanks

1st term: 3*1+2=5
2nd term: 3*2+2=8
3rd term: 3*3+2=11
10th term: 3*10+2=32

The nth term of a sequence is 3n + 2 A) work out the first 3 terms in the sequence B) work out the 10th term in the sequenc

1% of 75 is 0.01*75=0.75 so 3% of 75=3*0.75=2.25. 20% of75 is just 75/5=15. So 23% of 75 is 15+2.25=17.25.

Twenty three percent of seventy five what is the answe

Parallel lines have the same gradient so the coefficient of x must still be 2. We know one set of x and y values so we can substitute in to get 7=0*2+c and rearrange to get c=7
Thus the equation of the parallel line is y=2x+7.

How do you work out what the equation of the parallel line to my=2x+3 and passes through (0,7) is

Rearrange the equation for the straight line to the form: ax+b=y and substitute this result for y into the equation for the circle (x-c)^2+(y-d)^2=e and you can rearrange to get a quadratic in x. Solve the quadratic. Since the line is a tangent to the circle, there will only be one repeated solution, which gives the x coordinate you are after. Substitute back into the equation of the line to find your y value.

How do I find the point of contact of a tangent to a curve or circle

Completing the square simply means putting a quadratic into perfect square form and then adjusting for the constant term. This means rearranging the equation
ax^2+bc+c=0 to
a(x+b/a)^2-b^2/a +c=0

How do I solve quadratics by completing the squares? I’ve looked it up, but I don’t get it and I have homework due on it

Standard deviation can be found by first calculating the variance given by mean of the squares - square of the means. Taking the square root of this gives the standard deviation, a measure of average distance of each data point from the mean.


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Dan Ritchie