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faizah Begum

Hiiii, I want to get you amazing gcse results

11 questions answered
Under 5 hours taught

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Hi, I'm faizah

I have recently done the new gcse 9-1 exams and have passed with grades 6-8 in all subjects. I will be best at teaching the separate sciences the best as I have experienced the new exams. I understand the stress as my year was the first to do these exams but don’t worry I have your back, and will try my best to explain the content to you. I will not let you go a lesson without understanding something properly. Also I have tonnes of resources that you can use.

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My top answers

Asked by SophiΓ©

Maths πŸ’―
How do I find the point of contact of a tangent to a curve or circle
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faizah Begum

Hiiii, I want to get you amazing gcse results

The equation of the circle is: (x-a)^2 + (y-b)^2 = r^2 The equation of the tangent (linear ofc) is: y=mx+c At the point of contact for these lines,...Learn more

Asked by Josh

Maths πŸ’―
How do I find the area of a triangle when I only know the three side lengths
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faizah Begum

Hiiii, I want to get you amazing gcse results

There are two methods to find the area: Method 1: use cosine rule to find out one angle: cosA=(b^2+c^2-a^2)/2bc, and then use area formula 1/2bcSin...Learn more

Asked by Monita

Maths πŸ’―
Maths question Gradient of a line y=mx + c
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faizah Begum

Hiiii, I want to get you amazing gcse results

Yes of a linear line where m is the gradient (steepness of the line) and c is the y intercept (where the line hits the y-axis).

Asked by Bella

Maths πŸ’―
What’s the equation of a line on a graph with points of (3,-3) (-2,2)
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faizah Begum

Hiiii, I want to get you amazing gcse results

To find an equation of a line you must know it’s gradient (how steep the line is) to do this you use the formula Y2-Y1/X2-X1 2β€”3/-2-3 or change i...Learn more

Asked by Bella

Maths πŸ’―
How do I find the equation of a line on a graph using the equation y=mx+c
Verified

faizah Begum

Hiiii, I want to get you amazing gcse results

To find an equation of a line you must know it’s gradient (how steep the line is) to do this you use the formula Y2-Y1/X2-X1 or change in y divid...Learn more