If the ratio of the sides is 2, 3 and 4, we can say that an equal part x is part of each quantity. Hence 2x, 3x, and 4x. These are the lengths of the triangle. The perimeter is 108 and adding the lengths gives 9x. Therefore x is 12. 
Lengths are: 2*12 = 24, 3*12 =36, 4*12=  48

Maths

If the side lengths of triangle ABC have the ratio 2 : 3 :4 and the perimeter is 108 calculate each side length for triangle ABC?

Firstly, 
A quadratic equation is given as: 
ax^2 +bx +c = 0
Sum of roots = -b/a
Product of roots = c/a

Sum of roots = -1/2  
-b/a = -1/2
b = 1 a = 2

Product of roots = -3
c/a = -3
c = -6
ax^2 + bx + c = 0
2x^2 + x -6 = 0

Just change the sIgn of the zeroes and wrIte : (X+1/2)(X+3)=x^2+1/2x+3x+3/2= x^2+7/2x+3/2

The sum and product of the zeroes of a quadratic polynomial are -1/2 and -3 respectively.Form a quadratic polynomial?

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