Experienced

Valuable

Let's use simultaneous equations for this question.
y will be the larger number and x being the smaller number.
The sum is 45 so: x + y = 45 (eq1)
The larger number is 3 less than twice the smaller number. Changing this to an equation becomes
y = 2x - 3 (eq2)
Let's use substitution and substitute eq2 into eq1

x + (2x - 3) = 45
Simplify 
3x - 3 = 45
Move the -3 to the right hand side, this will change the sign
3x = 45 + 3
3x = 48
Divide both sides by 3 
x = 16

Now that we know the value of the smaller number, we can substitute it into eq2 to find y

y = 2x - 3
Becomes
y = 2(16) - 3
y = 29

Let's check 
29 + 16 = 45 


Maths

The sum of two numbers is 45. The larger number is 3 less than twice the smaller. Find the two numbers.

3/4 × 24 = 18 wins 
She then won 12 more games bringing her wins to 30. Out of 36 games, 30 were wins and 6 were loses. Therefore,

Wins : Loses
   30  :    6

Divide both by 6 to simplify to
W : L
 5 :  1

Anna plays a computer game.Each game is a win or a loss. She wins three quarters of her first 24 games. She then wins her next 12 games.For all 36 games, work out the ratio wins : lossesGive your answer in its simplest form.

Two ways to work this out. If you are given the diameter then use pi x diameter. If you are given the radius then do 2 x pi x radius.

Nuzha Ramankhan

Profile

Q&A

About

Nuzha is verified

Education

University College London (UCL)

University College London (UCL)

London Metropolitan University

Availability

Subjects

Nuzha Ramankhan