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If we take 37 as the 0th term, then the nth term can be found as 37-4n, as each following number is smaller by a common difference of 4.
For example: 4th term (21) = 37-4*4 = 37-16 = 21.

If we consider 37 to be the 1st term, we need to make a small change to our formula: 37-4(n-1)
Now: 5th term (21) = 37-4*(5-1) = 37-16 = 21.

Maths

Possible formuna for the nth term of a sequence of 37 33 29 25 21

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